You returned a pointer to a temporary. It's nasty but easy to spot.
Would you return `input.c_str()`? You might think twice about that, but it's the same thing. My favorite fix is to take a `std::string_view` as the parameter.
The result of the undefined behavior in your program is surprising, though. As it usually is.
quuxplusone 10 hours ago [-]
This is why I call string_view a "parameter-only type": it's fine to take as a parameter, but not fine to return or to store as a variable. (For sane definitions of "fine" and "not fine," of course. The blog post demonstrates one way it can go "not fine.")
but when using it as a parameter it IS stored as a variable, just only within that function, right?
stefanos82 13 hours ago [-]
With GCC and `-fsanitize=address,undefined` flag(s) I have catched it during runtime.
I've got a nice `==31604==ERROR: AddressSanitizer: stack-use-after-scope on address`
dingaling911 9 hours ago [-]
Oh this is nasty. But the proposed solution of making admin_id a singleton is weird.
The real fix is don't pass in a temporary to the sanitize function.
blastonico 9 hours ago [-]
std::string_view username = Sanitize("foobarbazboo");
^- temporary std::string created here
std::string_view Sanitize(const std::string& input) { ... }
^ ^- reference to that temporary string
+- returns a view to a temporary string
std::string_view username = // possibly data freed and dangling string
ranger_danger 10 hours ago [-]
> For example, this only works because the string foobarbazboo is the same length as admin_id
12 != 8
I don't get it...
> As you can guess, this is an example of undefined behavior causing unintuitive results.
No I couldn't... and what undefined behavior where? They don't explain anything.
aw1621107 4 hours ago [-]
The other comments explained the same-length part.
As for the rest of the bug, my guess is:
1. Construct a temporary std::string for "foobarbazbug". The length of this string is 12 so it's stored on the stack due to the short/small string optimization.
2. Call Sanitize, passing a pointer to the temporary
3. Store the return value of Sanitize. Note that this return value is basically a pointer to the entire contents of the temporary, which due to SSO means the return value is actually a pointer to a specific bit of stack memory
4. Destroy the temporary.
5. Construct a std::string for the admin_id, reusing the stack slot for the temporary. This data also ends up on the stack due to SSO.
6. username == admin_id. username points to the stack memory formerly occupied by the argument passed to Sanitize(), which is now occupied by admin_id. As a result this comparison is effectively admin_id == admin_id, which is obviously true.
I suspect (but can't check for now) that due to the dependence on SSO lengths up to 16 should work in general, up to 22 (or 23? Can't remember) should work for libc++, and beyond that is not very likely to work at all.
dingaling911 9 hours ago [-]
He means the string value of the variable admin_id, not the variable name admin_id.
And the bug comes from the temporary string object created when he passes in the string to Sanitize.
Sanitize("foobarbaz") -> creates temporary string -> string_view from temporary string -> returns string_view of temporary string
temporary string destructed
operations on returned string_view -> oops, use after free.q
ranger_danger 9 hours ago [-]
But if Sanitize has a return type of string_view, then returning the temporary variable should make a copy of it (or move it), right? And the string "foobarbazboo" is static so that's not being freed either.
And the while loop shouldn't even run at all since front() never equals ' '.
dingaling911 8 hours ago [-]
string_view is literally a reference. Copying a string_view just copies the reference.
ranger_danger 8 hours ago [-]
But it's not actually taken as a reference (with &) anywhere I see... and even if it's just internally referencing the (static) string, there shouldn't be any issue with that memory either right?
aw1621107 4 hours ago [-]
> But it's not actually taken as a reference (with &) anywhere I see...
That is effectively what is happening internally. A string_view is morally a pointer/length pair; that pointer has to be initialized somehow.
> and even if it's just internally referencing the (static) string
It's not. The function call constructs a temporary std::string from the string literal, but once that is done the contents of the temporary are entirely independent from the string literal.
magackame 10 hours ago [-]
The value of `admin_id` is "root_1231231", which is indeed the same length as "foobarbazboo". Otherwise, yeah, no idea where the bug comes from.
Rendered at 10:31:35 GMT+0000 (Coordinated Universal Time) with Vercel.
Would you return `input.c_str()`? You might think twice about that, but it's the same thing. My favorite fix is to take a `std::string_view` as the parameter.
The result of the undefined behavior in your program is surprising, though. As it usually is.https://quuxplusone.github.io/blog/2018/03/27/string-view-is...
I've got a nice `==31604==ERROR: AddressSanitizer: stack-use-after-scope on address`
The real fix is don't pass in a temporary to the sanitize function.
12 != 8
I don't get it...
> As you can guess, this is an example of undefined behavior causing unintuitive results.
No I couldn't... and what undefined behavior where? They don't explain anything.
As for the rest of the bug, my guess is:
1. Construct a temporary std::string for "foobarbazbug". The length of this string is 12 so it's stored on the stack due to the short/small string optimization.
2. Call Sanitize, passing a pointer to the temporary
3. Store the return value of Sanitize. Note that this return value is basically a pointer to the entire contents of the temporary, which due to SSO means the return value is actually a pointer to a specific bit of stack memory
4. Destroy the temporary.
5. Construct a std::string for the admin_id, reusing the stack slot for the temporary. This data also ends up on the stack due to SSO.
6. username == admin_id. username points to the stack memory formerly occupied by the argument passed to Sanitize(), which is now occupied by admin_id. As a result this comparison is effectively admin_id == admin_id, which is obviously true.
I suspect (but can't check for now) that due to the dependence on SSO lengths up to 16 should work in general, up to 22 (or 23? Can't remember) should work for libc++, and beyond that is not very likely to work at all.
And the bug comes from the temporary string object created when he passes in the string to Sanitize.
Sanitize("foobarbaz") -> creates temporary string -> string_view from temporary string -> returns string_view of temporary string
temporary string destructed
operations on returned string_view -> oops, use after free.q
And the while loop shouldn't even run at all since front() never equals ' '.
That is effectively what is happening internally. A string_view is morally a pointer/length pair; that pointer has to be initialized somehow.
> and even if it's just internally referencing the (static) string
It's not. The function call constructs a temporary std::string from the string literal, but once that is done the contents of the temporary are entirely independent from the string literal.